How do you evaluate #(27\div 9) ^ { 2} - 4#?

Answer 1

The answer is #5#.

Apply the order of operations: parentheses/brackets; exponents/powers; multiplication and division from left to right; addition and subtraction from left to right. A way to remember this is the acronym PEMDAS.

#(27-:9)^2-4#

Carry out the operation within the parentheses.

#(3)^2-4#

Apply the exponent.

#3^2-4#

#9-4#

Subtract #4# from #9#.

#5#

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Answer 2

Gabriel Agustin

To evaluate ((27\div 9)^2 - 4), follow the order of operations, which is parentheses, exponents, multiplication and division (from left to right), and addition and subtraction (from left to right).

First, evaluate the expression inside the parentheses: (27\div 9 = 3).

Next, square the result: (3^2 = 9).

Then, subtract (4) from (9): (9 - 4 = 5).

So, ((27\div 9)^2 - 4 = 5).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.