How do you evaluate #2 imes \{ 6+ [ 12\div ( 3+ 1) ] \} - 1#?

Question

How do you evaluate #2	imes \{ 6+ [ 12\div ( 3+ 1) ] \} - 1#?

Aurora Arias · Accepted Answer

First work the parentheses from inside out. After that the multiplication and then the subtraction.

#=2xx{6+[12div4]}-1# #=2xx{6+3}-1# #=2xx9-1# #=18-1# #=17#

Riley Anderson · Answer

undefined To evaluate the expression $2\times \{ 6+ [ 12\div ( 3+ 1) ] \} - 1$, follow the order of operations, which is Parentheses, Exponents, Multiplication and Division (from left to right), and Addition and Subtraction (from left to right):

1. First, solve the expression inside the innermost parentheses: $3+1 = 4$.
2. Next, solve the expression inside the brackets: $12\div 4 = 3$.
3. Then, evaluate the expression inside the curly braces: $6 + 3 = 9$.
4. Now, multiply 2 by 9: $2 \times 9 = 18$.
5. Finally, subtract 1 from 18: $18 - 1 = 17$.

So, $2\times \{ 6+ [ 12\div ( 3+ 1) ] \} - 1$ equals 17.

Autumn Arnold · Answer

undefined To evaluate the expression $2 \times \{ 6 + [12 \div (3 + 1)] \} - 1$, follow the order of operations, also known as PEMDAS (Parentheses, Exponents, Multiplication and Division, Addition and Subtraction):

1. Begin by evaluating expressions within innermost parentheses first.
2. Then proceed outward, evaluating expressions within brackets.
3. Finally, perform any multiplication, division, addition, and subtraction operations in the correct order.

Let's solve it step by step:

1. Evaluate the expression inside the parentheses: $12 \div (3 + 1) = 12 \div 4 = 3$.
2. Substitute the result back into the expression: $2 \times \{6 + [3]\} - 1$.
3. Evaluate the expression within the curly braces: $6 + 3 = 9$.
4. Substitute the result back into the expression: $2 \times 9 - 1$.
5. Perform the multiplication: $2 \times 9 = 18$.
6. Perform the subtraction: $18 - 1 = 17$.

So, $2 \times \{ 6 + [12 \div (3 + 1)] \} - 1 = 17$.

How do you evaluate #2\times \{ 6+ [ 12\div ( 3+ 1) ] \} - 1#?