How do you evaluate #2\frac{1}{3]-1\frac{1}{2}#?

Question

Everly Taylor · Accepted Answer

#5/6#

First, change the mixed fractions into improper fractions by multiplying the whole number by the denominator and then adding the numerator.

#2 1/3= (2xx3+1)/3 = 7/3#

#1 1/2= (1xx2+1)/2 = 3/2#

Next, find a common denominator and then multiply the top and the bottom by the same number.

#7/3 xx 2/2 = 14/6#

#3/2 xx 3/3 = 9/6#

Subtract the numerators.

#14-9= 5#

Make sure to keep the denominator.

#5/6#

Gianna Caruso · Answer

#5/6#

Step 1: You have to Multiply the #3# and the #2# together and then add the #1# and that would all be over #3#. Then you get

#2 1/3 = (2 xx 3 + 1)/3 = 7/3#

Step 2: You do the same thing which is #2# times #1# and then add #1# and that would be all over #2#. Then you get

#1 1/2 = (1 xx 2 + 1)/2 = 3/2#

Step 3: Combine together as

#7/3 - 3/2#

Next, you have to have a common denominator of #6#. #7/3# times #2# both top and bottom. Then #3/2# is going to be times #3# both top and bottom.

#7/3 xx 2/2 = (7 xx 2)/(3 xx 2)#

#3/2 xx 3/3 = (3 xx 3)/(2 xx 3)#

Next, multiply top and bottom fractions individually, which gets to be

#14/6 - 9/6 = (14 - 9)/6 = 5/6#

Luna Angel · Answer

undefined To evaluate $2\frac{1}{3} - 1\frac{1}{2}$, follow these steps:

1. Convert the mixed numbers to improper fractions.
   $2\frac{1}{3}$ as an improper fraction is $\frac{7}{3}$.
   $1\frac{1}{2}$ as an improper fraction is $\frac{3}{2}$.

2. Subtract the fractions:
   $$\frac{7}{3} - \frac{3}{2}$$

3. To subtract fractions, ensure that the denominators are the same. In this case, we need to find a common denominator for 3 and 2, which is 6.

4. Rewrite each fraction with the common denominator:
   $$\frac{7}{3} = \frac{7 \times 2}{3 \times 2} = \frac{14}{6}$$
   $$\frac{3}{2} = \frac{3 \times 3}{2 \times 3} = \frac{9}{6}$$

5. Now subtract the fractions:
   $$\frac{14}{6} - \frac{9}{6} = \frac{14 - 9}{6} = \frac{5}{6}$$

Therefore, $2\frac{1}{3} - 1\frac{1}{2} = \frac{5}{6}$.