How do you evaluate #18- [ 12\div ( 15\div ( 8- 7- 4) ) + 6\}#?

Answer 1

#14.4#

Remember: PEMDAS

Start with #(8-7-4) = -3#
The expression would look like: #18 - #[#12 divide (15 divide -3) + 6]#
2nd: #15# divided by #-3# is #15/-3=-5#
The expression would look like: #18 - #[#12 divide -5 + 6]#
3rd: #12# divided by #-5# is #12/-5=-2.4#
4th: #-2.4 + 6 = 3.6#
The expression would look like: #18 - 3.6#
5th: #18 - 3.6 = 14.4 #
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Answer 2

The result of the expression 18 - [ 12 ÷ ( 15 ÷ ( 8 - 7 - 4) ) + 6 ] is 18.

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Answer 3

Evaluate 18 - [12 ÷ (15 ÷ (8 - 7 - 4)) + 6]:

First, evaluate the expression inside the innermost parentheses, from left to right: 8 - 7 - 4 = -3

Now, calculate 15 ÷ (-3): 15 ÷ (-3) = -5

Next, substitute the result (-5) back into the original expression: 12 ÷ (-5) = -2.4

Now, calculate the outer expression: -2.4 + 6 = 3.6

Finally, subtract 3.6 from 18: 18 - 3.6 = 14.4

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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