How do you evaluate #12 \frac { 1} { 3} - 5\frac { 5} { 6}#?

Question

Cameron Arnold · Accepted Answer

#6 1/2# #12 1/3 - 5 5/6# #= 7 " "+1/3-5/6" "larr#subtract the whole numbers #=7 (2-5)/6" "larr# find a common denominator #= 6 (6+2-5)/6" "larr# convert a whole number: #1 = 6/6# #=6 1/2" "larr# simplify the numerator

Jeremiah Andrews · Answer

The answer is #13/2#

or #6 1/2# First lets convert the mixed fractions into improper fractions (or whatever you want to call them) getting #37/3# - #-35/6#. To get them both to have the same denominator we can multiply the first fraction by #2/2# to get: #74/6# -#35/6#, giving us #39/6#, or #13/2#

Skylar Adams · Answer

undefined To evaluate $12 \frac{1}{3} - 5\frac{5}{6}$, you need to subtract the two mixed numbers:

$12 \frac{1}{3} - 5\frac{5}{6} = (12 + \frac{1}{3}) - (5 + \frac{5}{6})$

Now, find a common denominator for the fractions:

$12 \frac{1}{3} - 5\frac{5}{6} = (12 + \frac{1}{3}) - (5 + \frac{5}{6}) = (12 + \frac{2}{6}) - (5 + \frac{5}{6})$

$12 \frac{1}{3} - 5\frac{5}{6} = (12 + \frac{2}{6}) - (5 + \frac{5}{6}) = (12 + \frac{2}{6}) - (5 + \frac{5}{6})$

Now, perform the addition and subtraction:

$12 \frac{1}{3} - 5\frac{5}{6} = (12 + \frac{2}{6}) - (5 + \frac{5}{6}) = (12 + \frac{2}{6}) - (5 + \frac{5}{6}) = 12 + \frac{2 - 5}{6} - 5 - \frac{5}{6}$

$12 \frac{1}{3} - 5\frac{5}{6} = (12 + \frac{2}{6}) - (5 + \frac{5}{6}) = (12 + \frac{2}{6}) - (5 + \frac{5}{6}) = 12 + \frac{-3}{6} - 5 - \frac{5}{6}$

Now, simplify:

$12 \frac{1}{3} - 5\frac{5}{6} = (12 + \frac{2}{6}) - (5 + \frac{5}{6}) = (12 + \frac{2}{6}) - (5 + \frac{5}{6}) = 12 - \frac{1}{2} - 5 - \frac{5}{6}$

$12 \frac{1}{3} - 5\frac{5}{6} = (12 + \frac{2}{6}) - (5 + \frac{5}{6}) = (12 + \frac{2}{6}) - (5 + \frac{5}{6}) = 11\frac{1}{2} - 5 - \frac{5}{6}$

Now, subtract:

$12 \frac{1}{3} - 5\frac{5}{6} = (12 + \frac{2}{6}) - (5 + \frac{5}{6}) = (12 + \frac{2}{6}) - (5 + \frac{5}{6}) = 11\frac{1}{2} - 5 - \frac{5}{6} = 11\frac{1}{2} - 5 - \frac{5}{6} = 6\frac{1}{2} - \frac{5}{6}$

Now, subtract the fractions:

$12 \frac{1}{3} - 5\frac{5}{6} = (12 + \frac{2}{6}) - (5 + \frac{5}{6}) = (12 + \frac{2}{6}) - (5 + \frac{5}{6}) = 11\frac{1}{2} - 5 - \frac{5}{6} = 11\frac{1}{2} - 5 - \frac{5}{6} = 6\frac{1}{2} - \frac{5}{6} = 6\frac{1}{2} - \frac{5}{6}$

Convert $6\frac{1}{2}$ to a fraction with a denominator of 6:

$6\frac{1}{2} = 6 + \frac{1}{2} = 6\frac{3}{6}$

Now, subtract:

$6\frac{3}{6} - \frac{5}{6} = 6 - 5 + \frac{3}{6} - \frac{5}{6} = 1 + \frac{3 - 5}{6} = 1 - \frac{2}{6} = 1 - \frac{1}{3}$

So, $12 \frac{1}{3} - 5\frac{5}{6} = 1\frac{1}{3}$.