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How do you evaluate #0.50[ x + ( x + 0.25x ) ]#?

Answer 1

1.125x

Braces are to be removed from inner to outer in that order to evaluate. #0.5[x+x+0.25x] color(white)((@@)# removing ( ) bracket #0.50[2.25x]=0.50*2.25x=(50/100)*((225/100)x# #(50*225*x)/((100)(100))=(1125cancel(0)x)/(1000cancel(0))=1.125x#

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Answer 2

Hazel Anglin

To evaluate the expression 0.50[x + (x + 0.25x)], follow the order of operations (PEMDAS/BODMAS):

Start by simplifying within the parentheses: (x + 0.25x) = 1.25x
Then, rewrite the expression with the simplified term: 0.50[x + 1.25x]
Combine like terms within the brackets: 0.50 * (2.25x) = 1.125x

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.