# How do you draw the slope field of the differential equation #y'=y-x# ?

You have to substitute values of

To draw these slope field may be a little bit challenging but you can use softwares that can help you to do that, such as the one from:

https://tutor.hix.ai

In your case you may use pencil and paper and draw at each point a little line with inclination representing the value calculated at that point.

Have a look at the drawing obtained from the above website using your equation:

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To draw the slope field of the differential equation ( y' = y - x ), you need to evaluate the expression ( y - x ) for various values of x and y. Then, at each point (x, y), you draw a short line segment with slope equal to the value of ( y - x ) at that point. Repeat this process for different values of x and y to sketch the slope field.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

- What is a solution to the differential equation #e^ydy/dt=3t^2+1#?
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- What is the general solution of the differential equation? : # dy/dx + (2x)/(x^2+1)y=1/(x^2+1) #
- What is the arclength of #f(x)=x-sqrt(e^x-2lnx)# on #x in [1,2]#?
- How do you find the length of the curve #y=sqrt(x-x^2)#?

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