# How do you draw the line with the slope #m=1/2# and #y#- intercept #5#?

graph{y = 1/2x + 5 [-9.29, 10.71, 1.32, 11.32]}

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Start at the y-intercept and count

Join the points with a straight line.

graph{1/2x+5 [-19.73, 20.27, -7.08, 12.92]}

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To draw a line with a slope of ( \frac{1}{2} ) and a y-intercept of 5, you can start by plotting the y-intercept point on the y-axis at y = 5. Then, you can use the slope to determine additional points on the line. Since the slope is ( \frac{1}{2} ), you can interpret it as "rise over run," meaning for every 1 unit increase in the y-direction, there is a 2 unit increase in the x-direction. Therefore, from the y-intercept point (0,5), you can move up 1 unit and to the right 2 units to find another point on the line. Repeat this process to find more points, and then connect them to draw the line.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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