# How do you divide #(x^4+2x^3+ 15 x^2+6x+8)/(x-4) #?

Use "long division" or "synthetic division" for this division.

synthetic division #{: (,,x^4,x^3,x^2,x^1,x^0," usually omitted"), (,,1,2,15,6,8," the coefficients"), (ul(+),ul(color(white)("|")),ul(0),ul(4),ul(24),ul(146),ul(608)," product of prior row 3 value and "x"'s zero"), (4,"|",1,6,39,152,616," the 4 is the value of "x" that would make the denominator "=0), (,,x^3,x^2,x^1,x^0,R," again, this is usually omitted") :}#

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To divide (x^4+2x^3+15x^2+6x+8) by (x-4), you can use long division. Here are the steps:

- Divide the first term of the numerator (x^4) by the first term of the denominator (x). This gives x^3.
- Multiply the entire denominator (x-4) by the quotient obtained in step 1 (x^3). This gives x^3(x-4) = x^4-4x^3.
- Subtract the result obtained in step 2 from the numerator (x^4+2x^3+15x^2+6x+8) to get the new numerator: (2x^3+15x^2+6x+8) - (x^4-4x^3) = -x^4+6x^3+15x^2+6x+8.
- Repeat steps 1-3 with the new numerator (-x^4+6x^3+15x^2+6x+8) until the degree of the new numerator is less than the degree of the denominator.
- The final quotient is the sum of all the quotients obtained in each step. In this case, the quotient is x^3.

Therefore, (x^4+2x^3+15x^2+6x+8)/(x-4) = x^3.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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- How do you graph #(-5x)/(x+3)#?

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