How do you divide #(x^3 - 2x^2 - 4x + 5) /( x - 3)#?
The solution of the expression is:
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To divide (x^3 - 2x^2 - 4x + 5) by (x - 3), we can use long division.
First, divide x^3 by x, which gives us x^2. Multiply (x - 3) by x^2, which gives us x^3 - 3x^2. Subtract this from the original polynomial to get (-x^2 - 4x + 5).
Next, divide -x^2 by x, which gives us -x. Multiply (x - 3) by -x, which gives us -x^2 + 3x. Subtract this from the previous result to get (-7x + 5).
Now, divide -7x by x, which gives us -7. Multiply (x - 3) by -7, which gives us -7x + 21. Subtract this from the previous result to get (-16).
Since we have no more terms to divide, the final result is x^2 - x - 7 with a remainder of -16.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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