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How do you divide #( x^3-2x^2 - 4x - 24 )/(x+2)#?

Answer 1

Eva Adamson

#x^2-4x+4+(16/(x+2))#

We use long polynomials di

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Answer 2

Eli Assouline

To divide (x^3-2x^2-4x-24) by (x+2), you can use long division.

First, divide x^3 by x, which gives you x^2. Multiply (x+2) by x^2, which gives you x^3+2x^2. Subtract this from the original polynomial to get -4x^2-4x-24.

Next, divide -4x^2 by x, which gives you -4x. Multiply (x+2) by -4x, which gives you -4x^2-8x. Subtract this from the previous result to get 4x-24.

Now, divide 4x by x, which gives you 4. Multiply (x+2) by 4, which gives you 4x+8. Subtract this from the previous result to get -32.

Since -32 is a constant term, there are no more terms to divide. Therefore, the final result is x^2-4x+4 with a remainder of -32.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.