# How do you divide #(x^2 + 7x – 6) / (x-6) # using polynomial long division?

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To divide (x^2 + 7x - 6) by (x - 6) using polynomial long division, follow these steps:

- Write the dividend (x^2 + 7x - 6) and the divisor (x - 6) in long division format.
- Divide the first term of the dividend (x^2) by the first term of the divisor (x). Write the result (x) above the line.
- Multiply the divisor (x - 6) by the result (x) and write the product (x^2 - 6x) below the dividend.
- Subtract the product (x^2 - 6x) from the dividend (x^2 + 7x - 6) and write the result (13x - 6) below the line.
- Bring down the next term from the dividend (-6) and write it next to the result (13x - 6).
- Divide the new dividend (13x - 6) by the first term of the divisor (x). Write the result (13) above the line.
- Multiply the divisor (x - 6) by the result (13) and write the product (13x - 78) below the new dividend.
- Subtract the product (13x - 78) from the new dividend (13x - 6) and write the result (72) below the line.
- Since there are no more terms to bring down, the division is complete.
- The quotient is the result written above the line, which is x + 13.
- The remainder is the result written below the line, which is 72.

Therefore, (x^2 + 7x - 6) divided by (x - 6) using polynomial long division is equal to x + 13 with a remainder of 72.

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