How do you divide #(x^2 - 5x + 4)/( x-2)#?

Answer 1

#x-3-2/(x-2)#

#"one way is to use the divisor as a factor in the numerator"#
#"consider the numerator"#
#color(red)(x)(x-2)color(magenta)(+2x)-5x+4#
#=color(red)(x)(x-2)color(red)(-3)(x-2)color(magenta)(-6)+4#
#=color(red)(x)(x-2)color(red)(-3)(x-2)-2#
#"quotient " =color(red)(x-3)," remainder "= -2#
#rArr(x^2-5x+4)/(x-2)=x-3-2/(x-2)#
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Answer 2

To divide (x^2 - 5x + 4) by (x-2), you can use long division or synthetic division. Here is the solution using long division:

     x - 3
---------------

x - 2 | x^2 - 5x + 4 - (x^2 - 2x) ------------- -3x + 4 - (-3x + 6) ------------ 2

Therefore, (x^2 - 5x + 4)/(x-2) simplifies to x - 3 with a remainder of 2.

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Answer 3

To divide (x^2 - 5x + 4) by (x - 2), you can use polynomial long division or synthetic division. Polynomial long division involves dividing the terms of the dividend by the divisor, similar to long division with numbers. Synthetic division is a quicker method that can only be used when the divisor is of the form (x - c), where c is a constant. You choose c = 2, as it is the root of the divisor. Both methods will yield the same quotient, which is x - 3.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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