# How do you divide #(x^2+5x-3)div(x-10)# using long division?

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Algebraic long division follows the same method as arithmetic long division...

Step 1. Write the dividend in the 'box' making sure that the indices are in descending powers of x.

Step 2. Divide the first term in divisor into the term in the dividend with the highest index. Write the answer at the top,

Step 3. Multiply by BOTH terms of the divisor at the side

Step 4. Subtract

Step 5. Bring down the next term

Repeat steps 2 to 5

This can also be written as

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To divide (x^2 + 5x - 3) by (x - 10) using long division, follow these steps:

- Divide the first term of the dividend by the first term of the divisor: (x^2) divided by (x) equals (x).
- Multiply the divisor by the result obtained in step 1: (x \times (x - 10)) equals (x^2 - 10x).
- Subtract the result obtained in step 2 from the dividend: (x^2 + 5x - 3 - (x^2 - 10x)) equals (15x - 3).
- Bring down the next term from the dividend: Bring down (15x).
- Repeat steps 1-3: Divide (15x) by (x), which equals (15). Multiply (x - 10) by (15), resulting in (15x - 150). Subtract this from (15x - 3), which equals (147).

So, (x^2 + 5x - 3) divided by (x - 10) equals (x + 15) with a remainder of (147).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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