How do you divide #(x^2+13x+12)/(x+2)div(x+1)#?

Answer 1
#f(x) = ((x + 1)(x + 12))/((x + 2)(x + 1)) = (x + 12)/(x + 2)#
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Answer 2

To divide (x^2+13x+12)/(x+2) by (x+1), you can use long division or synthetic division. Here is the step-by-step process using long division:

  1. Divide the first term of the numerator (x^2) by the first term of the denominator (x). This gives x as the first term of the quotient.
  2. Multiply the entire denominator (x+1) by x, and subtract the result from the numerator (x^2+13x+12).
    • (x+1) * x = x^2 + x
    • (x^2+13x+12) - (x^2 + x) = 12x + 12
  3. Bring down the next term from the numerator (-12x) and repeat the process.
  4. Divide (-12x) by (x) to get -12 as the next term of the quotient.
  5. Multiply the entire denominator (x+1) by -12, and subtract the result from the remaining numerator (12x + 12).
    • (x+1) * -12 = -12x - 12
    • (12x + 12) - (-12x - 12) = 24
  6. There are no more terms left in the numerator, so the remainder is 24.
  7. The final quotient is x - 12 with a remainder of 24.

Therefore, (x^2+13x+12)/(x+2) divided by (x+1) equals x - 12 with a remainder of 24.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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