# How do you divide #(t^2-16)/(t^2-8t+16)#?

#(t^2-16)/(t^2-8t+16) = 1+8/(t-4)#

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To divide (t^2-16)/(t^2-8t+16), we can use polynomial long division.

First, we divide the highest degree terms: t^2 ÷ t^2 = 1.

Next, we multiply the divisor (t^2-8t+16) by the quotient we obtained (1), giving us (t^2-8t+16).

We subtract this from the original dividend (t^2-16): (t^2-16) - (t^2-8t+16) = -8t.

Now, we bring down the next term, which is -8t.

We divide -8t ÷ t^2-8t+16, which gives us -8.

We multiply the divisor (t^2-8t+16) by the quotient we obtained (-8), giving us (-8t+64).

We subtract this from the previous result (-8t): (-8t) - (-8t+64) = -64.

Since there are no more terms to bring down, our final result is -8.

Therefore, (t^2-16)/(t^2-8t+16) simplifies to 1 - 8/(t^2-8t+16).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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