# How do you divide #\frac{x^2-25}{x+3} \-: (x-5)#?

In our case you have:

We can now manipulate the numerator of the first fraction as:

Substituting and simplifying:

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To divide (\frac{x^2-25}{x+3}) by ((x-5)), we can use polynomial long division.

First, we divide the highest degree term of the numerator by the highest degree term of the denominator. In this case, (\frac{x^2}{x}) gives us (x).

Next, we multiply the entire denominator ((x-5)) by the result (x), giving us (x(x-5) = x^2-5x).

We subtract this result from the numerator (x^2-25), which gives us ((x^2-25) - (x^2-5x)). Simplifying this expression, we get (-5x-25).

Since the degree of the resulting polynomial is less than the degree of the denominator, we cannot divide further.

Therefore, the division of (\frac{x^2-25}{x+3}) by ((x-5)) is equal to (x) with a remainder of (-5x-25).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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