# How do you divide #\frac { - \frac { 5} { 28x ^ { 2} } } { \frac { 10} { 21x ^ { 3} } }#?

See the entire solution process below:

First, rewrite this expression using this rule for dividing fractions:

Next, cancel common terms with the constants in the numerator and denominator:

Now, use these rules for exponents to complete the division:

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To divide the expression (\frac{-\frac{5}{28x^2}}{\frac{10}{21x^3}}), you can multiply the numerator by the reciprocal of the denominator.

This means you can rewrite the expression as:

(\frac{-\frac{5}{28x^2}}{\frac{10}{21x^3}} = -\frac{5}{28x^2} \times \frac{21x^3}{10})

Next, you can simplify this expression:

(-\frac{5}{28x^2} \times \frac{21x^3}{10} = -\frac{5 \times 21x^3}{28x^2 \times 10})

Now, simplify the expression further:

(-\frac{5 \times 21x^3}{28x^2 \times 10} = -\frac{105x}{280})

So, the division of (\frac{-\frac{5}{28x^2}}{\frac{10}{21x^3}}) simplifies to (-\frac{105x}{280}).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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