How do you divide #9x^2-16# by #3x+4#?

Answer 1
Treat your terms of your dividends like digits... However, you also need to consider "missing" terms (in the case of #9x^2 - 16#, the #x# term).

For your divisor, you need only divide using the first term

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Answer 2

To divide 9x^2-16 by 3x+4, you can use long division. The quotient will be 3x-4 and the remainder will be 0.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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