How do you divide #9x^2-16# by #3x+4#?
For your divisor, you need only divide using the first term
By signing up, you agree to our Terms of Service and Privacy Policy
To divide 9x^2-16 by 3x+4, you can use long division. The quotient will be 3x-4 and the remainder will be 0.
By signing up, you agree to our Terms of Service and Privacy Policy
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
- How do you simplify #\frac { 3x - 2} { 4- 6x } #?
- How do you solve #(x-1)/(x-2) - (x+1)/(x+2) = 4/(x^2-4)#?
- What polynomial yields a quotient of #2x-3# and a remainder of 3 when it divides #2x^2-7x+9#?
- How do you divide #(2x^3+7x^2-5x-4) / (2x+1)# using polynomial long division?
- How do you solve #(x - 2)/ 3 = 1/ x#?
- 98% accuracy study help
- Covers math, physics, chemistry, biology, and more
- Step-by-step, in-depth guides
- Readily available 24/7