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How do you divide #(-7x^3+5x^2+2x+5)/(x-4) #?

Answer 1

Make the denominator appear in the numerator.

#-7x^3 + 5 x^2 - 2x + 5 = (x-4)(-7x^2 - 33x - 130) - 520 + 5 # So the division by #x-4# yields #-7x^2 - 33x - 130 - 515/(x-4)#

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Answer 2

Eva Adamson

To divide (-7x^3+5x^2+2x+5) by (x-4), you can use long division. Here are the steps:

Divide the first term of the dividend (-7x^3) by the first term of the divisor (x). This gives you -7x^2.
Multiply the divisor (x-4) by -7x^2, which gives you -7x^3 + 28x^2.
Subtract this result from the original dividend (-7x^3+5x^2+2x+5) to get 5x^2 + 2x + 5 - (-7x^3 + 28x^2).
Simplify the expression obtained in step 3: 5x^2 + 2x + 5 + 7x^3 - 28x^2.
Repeat steps 1-4 with the simplified expression as the new dividend.
Continue this process until you have no more terms to divide.

The final result of the division is the quotient, which is -7x^2 + 28x + 7.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.