How do you divide #(6x^4+6x^3-12x^2-7x-7)/(x-2) #?
I got:
Synthetic division is a pretty simple method for doing it.
The coefficients of each term are used for this. It works similarly to standard long division but is quicker and/or more compact.
Thus, we start here:
Next, the fundamental actions are:
Thus, we would receive:
Simply reassign the coefficients to the polynomial solution. It is necessary for our answer to have decreased by one degree from the initial quartic.
Our response is a cubic, for this reason:
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To divide (6x^4+6x^3-12x^2-7x-7) by (x-2), you can use long division. Here are the steps:
- Divide the first term of the dividend (6x^4) by the first term of the divisor (x). The result is 6x^3.
- Multiply the entire divisor (x-2) by the result obtained in step 1 (6x^3). This gives you 6x^4-12x^3.
- Subtract the result obtained in step 2 from the original dividend (6x^4+6x^3-12x^2-7x-7). This gives you -6x^3-12x^2-7x-7.
- Bring down the next term from the dividend (-6x^3), and repeat steps 1-3 until you have no more terms to bring down.
- Repeat steps 1-4 until you have no more terms to bring down.
The final result of the division is 6x^3-12x^2-7x-7.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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