# How do you divide #(5x^2-2x+4)/(x-1)#?

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To divide (5x^2-2x+4) by (x-1), you can use long division or synthetic division. Here is the solution using long division:

```
5x + 3
_______________
```

x - 1 | 5x^2 - 2x + 4 - (5x^2 - 5x) _____________ 3x + 4 - (3x + 3) ___________ 1

Therefore, the quotient is 5x + 3 and the remainder is 1.

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To divide ( \frac{{5x^2 - 2x + 4}}{{x - 1}} ), you can use polynomial long division or synthetic division. Here's the process:

Step 1: Divide the first term of the numerator by the first term of the denominator to get the first term of the quotient. Step 2: Multiply the entire denominator by the first term of the quotient. Step 3: Subtract the result from the numerator. Step 4: Repeat steps 1-3 with the result obtained until the degree of the remainder is less than the degree of the denominator.

Applying these steps will give you the quotient and the remainder.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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