How do you divide #(4x^3 + x^2 – 3x – 4)/((x + 8) )#?
Once you get the hang of it, polynomial division is very similar to regular long division.
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To divide (4x^3 + x^2 – 3x – 4) by (x + 8), you can use long division. Here are the steps:
- Divide the first term of the dividend (4x^3) by the first term of the divisor (x). This gives you 4x^2.
- Multiply the entire divisor (x + 8) by the quotient obtained in step 1 (4x^2). This gives you 4x^3 + 32x^2.
- Subtract the result obtained in step 2 from the original dividend (4x^3 + x^2 – 3x – 4) to get the new dividend: (x^2 – 35x – 4).
- Repeat steps 1-3 with the new dividend (x^2 – 35x – 4) until you have no more terms to divide.
- The final quotient is the sum of all the quotients obtained in each step. In this case, the quotient is 4x^2.
Therefore, the division of (4x^3 + x^2 – 3x – 4) by (x + 8) is equal to 4x^2.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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