# How do you divide #(4x^3+2x-6) /(x-1)#?

See explanation

Bit long, but the process takes quite a bit of getting used to!

Since you inquired as to how to proceed, here is the procedure:

The demonstration in relation to this question.

Step 3.

The zeros indicate that our division is precise.

If there had only been a remainder of two, the response would be as follows:

It takes a lot of practice, hopefully this is helpful.

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To divide (4x^3+2x-6) by (x-1), you can use long division or synthetic division. Here is the solution using long division:

```
4x^2 + 4x + 6
_______________________
```

x - 1 | 4x^3 + 0x^2 + 2x - 6 - (4x^3 - 4x^2) ___________________ 4x^2 + 2x - (4x^2 - 4x) ______________ 6x - 6 - (6x - 6) __________ 0

Therefore, the quotient is 4x^2 + 4x + 6 and there is no remainder.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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