# How do you divide #(-4x^3-x^2+3x-4)/(x-3) #?

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I changed #(-4^3) rarr (-4x^3)# . Sorry if this is not what was intended, but it seemed more likely.

I changed

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To divide (-4x^3-x^2+3x-4) by (x-3), you can use long division. Here are the steps:

- Divide the first term of the numerator (-4x^3) by the first term of the denominator (x). This gives -4x^2.
- Multiply the entire denominator (x-3) by -4x^2, which gives -4x^3 + 12x^2.
- Subtract this result from the numerator: (-4x^3 - x^2 + 3x - 4) - (-4x^3 + 12x^2) = -13x^2 + 3x - 4.
- Bring down the next term from the numerator, which is 0x (since there is no x term).
- Divide the first term of the new numerator (-13x^2) by the first term of the denominator (x). This gives -13x.
- Multiply the entire denominator (x-3) by -13x, which gives -13x^2 + 39x.
- Subtract this result from the new numerator: (-13x^2 + 3x - 4) - (-13x^2 + 39x) = -36x - 4.
- Bring down the next term from the numerator, which is -36x.
- Divide the first term of the new numerator (-36x) by the first term of the denominator (x). This gives -36.
- Multiply the entire denominator (x-3) by -36, which gives -36x + 108.
- Subtract this result from the new numerator: (-36x - 4) - (-36x + 108) = -112.
- There are no more terms left in the numerator, so the division is complete.

The quotient is -4x^2 - 13x - 36, and the remainder is -112.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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