# How do you divide #( -3x^3+ x^2-3x-28 )/(x + 1 )#?

The quotient is

Now let's divide that long way.

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To divide (-3x^3 + x^2 - 3x - 28) by (x + 1), you can use long division. Here are the steps:

- Divide the first term of the numerator (-3x^3) by the first term of the denominator (x). This gives -3x^2.
- Multiply the entire denominator (x + 1) by -3x^2, which gives -3x^3 - 3x^2.
- Subtract this result from the numerator: (-3x^3 + x^2 - 3x - 28) - (-3x^3 - 3x^2) = 4x^2 - 3x - 28.
- Bring down the next term from the numerator, which is -3x.
- Divide the first term of the new numerator (4x^2) by the first term of the denominator (x). This gives 4x.
- Multiply the entire denominator (x + 1) by 4x, which gives 4x^2 + 4x.
- Subtract this result from the new numerator: (4x^2 - 3x - 28) - (4x^2 + 4x) = -7x - 28.
- Bring down the next term from the numerator, which is -28.
- Divide the first term of the new numerator (-7x) by the first term of the denominator (x). This gives -7.
- Multiply the entire denominator (x + 1) by -7, which gives -7x - 7.
- Subtract this result from the new numerator: (-7x - 28) - (-7x - 7) = -21.
- There are no more terms left in the numerator, so the division is complete.

The quotient is -3x^2 + 4x - 7, and the remainder is -21.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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