How do you divide #(3x^3  x^2 + 3x 18)/(2x+2)#?
So,
And the remaining amount is 19
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To divide (3x^3  x^2 + 3x 18) by (2x+2), you can use long division. Here are the steps:

Divide the first term of the numerator (3x^3) by the first term of the denominator (2x). The result is 3/2x^2.

Multiply the entire denominator (2x+2) by the result obtained in step 1 (3/2x^2). This gives you (3/2x^2)(2x+2) = 3x  3.

Subtract the result obtained in step 2 (3x  3) from the numerator (3x^3  x^2 + 3x 18). This gives you (3x^3  x^2 + 3x 18)  (3x  3) = 3x^3  x^2 + 3x 18 + 3x + 3 = 3x^3  x^2 + 6x  15.

Repeat steps 13 with the new numerator (3x^3  x^2 + 6x  15) until the degree of the new numerator is less than the degree of the denominator.
In this case, the final result of the division is: 3/2x^2  3/4x  9/4.
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When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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