# How do you divide #( -3x^3+ 6x^2-13x-5 )/(x + 1 )#?

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To divide (-3x^3 + 6x^2 - 13x - 5) by (x + 1), you can use long division. Here are the steps:

- Divide the first term of the dividend (-3x^3) by the first term of the divisor (x). This gives -3x^2.
- Multiply the divisor (x + 1) by the result from step 1 (-3x^2), and write the product (-3x^3 - 3x^2) below the dividend.
- Subtract the product from the dividend: (-3x^3 + 6x^2 - 13x - 5) - (-3x^3 - 3x^2) = 9x^2 - 13x - 5.
- Bring down the next term from the dividend, which is -13x.
- Divide the first term of the new dividend (9x^2) by the first term of the divisor (x). This gives 9x.
- Multiply the divisor (x + 1) by the result from step 5 (9x), and write the product (9x^2 + 9x) below the new dividend.
- Subtract the product from the new dividend: (9x^2 - 13x - 5) - (9x^2 + 9x) = -22x - 5.
- Bring down the next term from the dividend, which is -5.
- Divide the first term of the new dividend (-22x) by the first term of the divisor (x). This gives -22.
- Multiply the divisor (x + 1) by the result from step 9 (-22), and write the product (-22x - 22) below the new dividend.
- Subtract the product from the new dividend: (-22x - 5) - (-22x - 22) = 17.
- There are no more terms in the dividend, so the division is complete.

The quotient is -3x^2 + 9x - 22, and the remainder is 17.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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