# How do you divide #(3x^3-6x^2+13x-4)/(x-3) #?

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To divide (3x^3-6x^2+13x-4) by (x-3), you can use long division. Here are the steps:

- Divide the first term of the dividend (3x^3) by the first term of the divisor (x). This gives you 3x^2.
- Multiply the entire divisor (x-3) by the quotient obtained in step 1 (3x^2). This gives you 3x^3 - 9x^2.
- Subtract the result obtained in step 2 from the original dividend (3x^3-6x^2+13x-4) to get a new polynomial: (-3x^2+13x-4).
- Bring down the next term from the original dividend (-3x^2) and repeat steps 1-3 until you have no more terms to bring down.

Continuing the process: 5. Divide (-3x^2) by (x), which gives you -3x. 6. Multiply the entire divisor (x-3) by the quotient obtained in step 5 (-3x). This gives you -3x^2 + 9x. 7. Subtract the result obtained in step 6 from the new polynomial (-3x^2+13x-4) to get a new polynomial: (4x-4). 8. Bring down the next term from the original dividend (4x) and repeat steps 5-7.

Continuing the process: 9. Divide (4x) by (x), which gives you 4. 10. Multiply the entire divisor (x-3) by the quotient obtained in step 9 (4). This gives you 4x - 12. 11. Subtract the result obtained in step 10 from the new polynomial (4x-4) to get a new polynomial: (8). 12. There are no more terms to bring down, so the division is complete.

The quotient is 3x^2 - 3x + 4, and the remainder is 8.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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