How do you divide #(3x^3 - 12x^2 - 11x - 20)/(x+5)#?

Answer 1

#(3x^3−12x^2−11x−20)/(x+5)=3x^2-27x+124-640/(x+5)#

#(3x^3−12x^2−11x−20)-:(x+5)=3x^2-27x+124# #(3x^3+15x^2)/# #color(white)(..)0-27x^2-11x-20# #color(white)(....)(-27x^2-135x)/# #color(white)(...........)0+124x-20# #color(white)(..............)(+124x+620)/# #color(white)(......................)0-640#
#(3x^3−12x^2−11x−20)/(x+5)=3x^2-27x+124+(-640)/(x+5)#
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Answer 2

#3x^2-27x+124-640/(x+5)#

#"one way is to use the divisor as a factor in the numerator"#
#"consider the numerator"#
#color(red)(3x^2)(x+5)color(magenta)(-15x^2)-12x^2-11x-20#
#=color(red)(3x^2)(x+5)color(red)(-27x)(x+5)color(magenta)(+135x)-11x-20#
#=color(red)(3x^2)(x+5)color(red)(-27x)(x+5)color(red)(+124)(x+5)color(magenta)(-620)-20#
#=color(red)(3x^2)(x+5)color(red)(-27x)(x+5)color(red)(+124)(x+5)-640#
#"quotient "=color(red)(3x^2-27x+124)," remainder "=-640#
#rArr(3x^3-12x^2-11x-20)/(x+5)#
#=3x^2-27x+124-640/(x+5)#
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Answer 3

To divide (3x^3 - 12x^2 - 11x - 20) by (x+5), you can use long division. Here are the steps:

  1. Divide the first term of the dividend (3x^3) by the first term of the divisor (x). This gives you 3x^2.
  2. Multiply the divisor (x+5) by the quotient obtained in step 1 (3x^2). This gives you 3x^3 + 15x^2.
  3. Subtract the result obtained in step 2 from the dividend (3x^3 - 12x^2 - 11x - 20) to get a new polynomial: -27x^2 - 11x - 20.
  4. Repeat steps 1-3 with the new polynomial (-27x^2 - 11x - 20).
    • Divide the first term of the new polynomial (-27x^2) by the first term of the divisor (x). This gives you -27x.
    • Multiply the divisor (x+5) by the quotient obtained (-27x). This gives you -27x^2 - 135x.
    • Subtract the result obtained from the new polynomial to get a new polynomial: 124x - 20.
  5. Repeat steps 1-3 with the new polynomial (124x - 20).
    • Divide the first term of the new polynomial (124x) by the first term of the divisor (x). This gives you 124.
    • Multiply the divisor (x+5) by the quotient obtained (124). This gives you 124x + 620.
    • Subtract the result obtained from the new polynomial to get a remainder of -640.

Therefore, the quotient is 3x^2 - 27x + 124 with a remainder of -640.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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