# How do you divide #(3x^3 - 12x^2 - 11x - 20)/(x+5)#?

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To divide (3x^3 - 12x^2 - 11x - 20) by (x+5), you can use long division. Here are the steps:

- Divide the first term of the dividend (3x^3) by the first term of the divisor (x). This gives you 3x^2.
- Multiply the divisor (x+5) by the quotient obtained in step 1 (3x^2). This gives you 3x^3 + 15x^2.
- Subtract the result obtained in step 2 from the dividend (3x^3 - 12x^2 - 11x - 20) to get a new polynomial: -27x^2 - 11x - 20.
- Repeat steps 1-3 with the new polynomial (-27x^2 - 11x - 20).
- Divide the first term of the new polynomial (-27x^2) by the first term of the divisor (x). This gives you -27x.
- Multiply the divisor (x+5) by the quotient obtained (-27x). This gives you -27x^2 - 135x.
- Subtract the result obtained from the new polynomial to get a new polynomial: 124x - 20.

- Repeat steps 1-3 with the new polynomial (124x - 20).
- Divide the first term of the new polynomial (124x) by the first term of the divisor (x). This gives you 124.
- Multiply the divisor (x+5) by the quotient obtained (124). This gives you 124x + 620.
- Subtract the result obtained from the new polynomial to get a remainder of -640.

Therefore, the quotient is 3x^2 - 27x + 124 with a remainder of -640.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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