How do you divide #3\frac { 2} { 3} + 4\frac { 3} { 7} =#?
Dividing gives: Adding gives
It seems there is a problem with the question:
Fractions which will give a recurring decimal are better left in fraction form which is accurate and does not entail any rounding off.
Add the whole numbers then find a common denominator and make equivalent fractions:
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To divide (3\frac{2}{3} + 4\frac{3}{7}), you first convert the mixed numbers to improper fractions, then perform the division.
(3\frac{2}{3}) as an improper fraction is (\frac{11}{3}) and (4\frac{3}{7}) as an improper fraction is (\frac{31}{7}).
So, the expression becomes (\frac{11}{3} + \frac{31}{7}).
To add fractions, they need a common denominator. The least common denominator for (3) and (7) is (21).
(\frac{11}{3} \times \frac{7}{7} = \frac{77}{21}) and (\frac{31}{7} \times \frac{3}{3} = \frac{93}{21}).
Now, the expression becomes (\frac{77}{21} + \frac{93}{21}).
Adding the numerators, (\frac{77 + 93}{21} = \frac{170}{21}).
Finally, simplify (\frac{170}{21}), if needed.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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