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How do you divide #(2x^3-x^2+7x+15)/(2x-5) #?

Answer 1

Genesis Allen

#x^2-2x+8.5#, with a remainder of #27.5#

Using polynomial long division:

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Answer 2

Eva Adamson

To divide (2x^3-x^2+7x+15) by (2x-5), you can use long division or synthetic division. Here is the solution using long division:

     x^2 + 2x + 5
---------------------

2x - 5 | 2x^3 - x^2 + 7x + 15 - (2x^3 - 5x^2) ----------------- 4x^2 + 7x - (4x^2 - 10x) --------------- 17x + 15 - (17x - 42) ------------- 57

Therefore, the quotient is x^2 + 2x + 5 and the remainder is 57.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.