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How do you divide #(2x^3-x^2-3x+1)/(x+2)#?

Answer 1

Julia Adams

#2x^2 - 5x -7 + frac{15}{x + 2}#

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Answer 2

Avery Alexander

To divide (2x^3-x^2-3x+1) by (x+2), you can use long division or synthetic division. Here is the solution using long division:

     2x^2 - 5x + 7
_______________________

x + 2 | 2x^3 - x^2 - 3x + 1 - (2x^3 + 4x^2) _________________ - 5x^2 - 3x + ( -5x^2 - 10x) __________________ 7x + 1 - (7x + 14) ______________ -13

Therefore, the quotient is 2x^2 - 5x + 7 and the remainder is -13.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.