How do you divide #(2x^3+7x^2+9x+15)/(3x1) #?
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To divide (2x^3+7x^2+9x+15) by (3x1), you can use long division. Here are the steps:

Divide the first term of the numerator (2x^3) by the first term of the denominator (3x). The result is 2/3x^2.

Multiply the entire denominator (3x1) by the result obtained in step 1 (2/3x^2). This gives you (2/3x^2)(3x1) = 2x + 2/3x^2.

Subtract the result obtained in step 2 from the numerator (2x^3+7x^2+9x+15) by changing the signs. This gives you (2x^3+7x^2+9x+15)  (2x + 2/3x^2) = 2x^3 + 7x^2 + 9x + 15 + 2x  2/3x^2.

Combine like terms in the resulting expression. In this case, you have 2x^3 + 2/3x^2 + 7x^2 + 2x + 9x + 15.

Repeat steps 14 with the new expression obtained in step 4 (2x^3 + 2/3x^2 + 7x^2 + 2x + 9x + 15) until you have no more terms to divide.
By following these steps, you can continue the long division process until you have divided all the terms and obtained a quotient.
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When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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