# How do you divide #(2x^3+4x^2-10x-9)÷(x-3)#?

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To divide (2x^3+4x^2-10x-9) by (x-3), you can use long division. Here are the steps:

- Divide the first term of the dividend (2x^3) by the first term of the divisor (x). The result is 2x^2.
- Multiply the divisor (x-3) by the quotient obtained in step 1 (2x^2). The result is 2x^3-6x^2.
- Subtract the result obtained in step 2 from the dividend (2x^3+4x^2-10x-9) to get the new dividend: (4x^2-10x-9).
- Repeat steps 1-3 with the new dividend (4x^2-10x-9).
- Divide the first term of the new dividend (4x^2) by the first term of the divisor (x). The result is 4x.
- Multiply the divisor (x-3) by the quotient obtained in step 5 (4x). The result is 4x^2-12x.
- Subtract the result obtained in step 6 from the new dividend (4x^2-10x-9) to get the new dividend: (2x-9).
- Repeat steps 1-3 with the new dividend (2x-9).
- Divide the first term of the new dividend (2x) by the first term of the divisor (x). The result is 2.
- Multiply the divisor (x-3) by the quotient obtained in step 9 (2). The result is 2x-6.
- Subtract the result obtained in step 10 from the new dividend (2x-9) to get the remainder: (-3).

Therefore, the quotient is 2x^2+4x+2 and the remainder is -3.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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