# How do you divide #(-2x^3-23x^2-4x+11)/(x-5) #?

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To divide (-2x^3-23x^2-4x+11) by (x-5), you can use long division. Here are the steps:

- Divide the first term of the numerator (-2x^3) by the first term of the denominator (x). The result is -2x^2.
- Multiply the entire denominator (x-5) by -2x^2, giving -2x^3 + 10x^2.
- Subtract this result from the original numerator: (-2x^3-23x^2-4x+11) - (-2x^3 + 10x^2) = -33x^2 - 4x + 11.
- Bring down the next term from the numerator, which is -33x^2. Now you have -33x^2 - 4x + 11.
- Divide the first term of this new numerator (-33x^2) by the first term of the denominator (x). The result is -33x.
- Multiply the entire denominator (x-5) by -33x, giving -33x^2 + 165x.
- Subtract this result from the new numerator: (-33x^2 - 4x + 11) - (-33x^2 + 165x) = -169x + 11.
- Bring down the next term from the numerator, which is -169x. Now you have -169x + 11.
- Divide the first term of this new numerator (-169x) by the first term of the denominator (x). The result is -169.
- Multiply the entire denominator (x-5) by -169, giving -169x + 845.
- Subtract this result from the new numerator: (-169x + 11) - (-169x + 845) = -834.
- There are no more terms left in the numerator, so the division is complete.

The quotient is -2x^2 - 33x - 169, and the remainder is -834.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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