How do you divide #(2x^2 + x – 16) /(x – 3)#?
I would use synthetic division.
This means that
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To divide (2x^2 + x – 16) by (x – 3), you can use long division or synthetic division. Here is the solution using long division:
2x + 7
_______________
x - 3 | 2x^2 + x - 16 - (2x^2 - 6x) _____________ 7x - 16 - (7x - 21) _____________ 5
Therefore, the quotient is 2x + 7 and the remainder is 5.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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