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How do you divide #(2x^2+8x+16) / (x-4) #?

Answer 1

Julia Adams

#2x+16+80/(x+4)#

#"one way is to use the divisor as a factor in the numerator"#

#"consider the numerator"#

#color(red)(2x)(x-4)color(magenta)(+8x)+8x+16#

#=color(red)(2x)(x-4)color(red)(+16)(x-4)color(magenta)(+64)+16#

#=color(red)(2x)(x-4)color(red)(+16)(x-4)+80#

#"quotient "=color(red)(2x+16)," remainder "=80#

#(2x^2+8x+16)/(x-4)=2x+16+80/(x-4)#

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Answer 2

Jameson Allen

To divide (2x^2+8x+16) by (x-4), you can use long division or synthetic division. Here is the solution using long division:

     2x + 16
_______________

x - 4 | 2x^2 + 8x + 16 - (2x^2 - 8x) _____________ 16x + 16 - (16x - 64) _____________ 80

Therefore, the quotient is 2x + 16 and the remainder is 80.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.