# How do you divide #(2x^2-3x+2)/(x - 1)#?

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#{: (,,,2x,-1), (,,"---","---","---"), (x-1,")",2x^2, -3x, -2), (,,2x^2,-2x,), (,,"---","---",), (,,,-x,-2), (,,,-x,+1), (,,"---","---","---"), (,,,,-3) :}#

Therfore,

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To divide (2x^2-3x+2) by (x - 1), we can use polynomial long division.

First, divide the highest degree term of the numerator (2x^2) by the highest degree term of the denominator (x). This gives us 2x as the quotient.

Next, multiply the entire denominator (x - 1) by the quotient (2x), which gives us 2x^2 - 2x.

Subtract this result from the numerator (2x^2 - 3x + 2) to get -x + 2.

Now, bring down the next term from the numerator (-x) and divide it by the highest degree term of the denominator (x). This gives us -1 as the next term of the quotient.

Multiply the entire denominator (x - 1) by the new quotient (-1), which gives us -x + 1.

Subtract this result from the previous remainder (-x + 2) to get 1.

Since the degree of the remainder (1) is less than the degree of the denominator (x - 1), we have finished the division.

Therefore, the quotient is 2x - 1 and the remainder is 1.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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