# How do you divide #(16x^6 - 12x^4 + 4x^2)# by #4x^2#?

It is

#[(16x^6 - 12x^4 + 4x^2)]/[4x^2]= 4x^2*[(4x^4-3x^2+1)]/[4x^2]= 4x^4-3x^2+1#

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To divide ( (16x^6 - 12x^4 + 4x^2) ) by ( 4x^2 ), you simply divide each term in the polynomial by ( 4x^2 ).

[ \frac{16x^6}{4x^2} = 4x^{6-2} = 4x^4 ] [ \frac{-12x^4}{4x^2} = -3x^{4-2} = -3x^2 ] [ \frac{4x^2}{4x^2} = 1 ]

So, the result of dividing ( (16x^6 - 12x^4 + 4x^2) ) by ( 4x^2 ) is ( 4x^4 - 3x^2 + 1 ).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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