How do you differentiate #y=(x^5+1)(3x^2-x)#?
The answer is
You apply the product role of differentiation
Here,
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To differentiate y=(x^5+1)(3x^2-x), apply the product rule, which states that the derivative of the product of two functions is the derivative of the first function times the second function plus the first function times the derivative of the second function.
So, the derivative of y with respect to x is:
dy/dx = (5x^4)(3x^2 - x) + (x^5 + 1)(6x - 1)
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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