How do you differentiate #y = (x^3 + 4)(-x^6 + x^4)#?
The easiest way is to simply multiply the two brackets
And then take the derivative of polinomials like this
You could use the product rule but this is a case where the simplest way is to foil the multiplication and then derive the result.
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To differentiate ( y = (x^3 + 4)(-x^6 + x^4) ), you can use the product rule. The product rule states that if you have two functions, ( u(x) ) and ( v(x) ), then the derivative of their product is given by:
[ \frac{d}{dx}(u \cdot v) = u'v + uv' ]
Where ( u' ) and ( v' ) are the derivatives of ( u(x) ) and ( v(x) ) with respect to ( x ), respectively.
So, applying the product rule to ( y = (x^3 + 4)(-x^6 + x^4) ), we get:
[ y' = (3x^2)(-x^6 + x^4) + (x^3 + 4)(-6x^5 + 4x^3) ]
[ y' = -3x^8 + 3x^6 - 6x^8 + 4x^6 - 24x^5 + 16x^3 ]
[ y' = -9x^8 + 7x^6 - 24x^5 + 16x^3 ]
So, the derivative of ( y = (x^3 + 4)(-x^6 + x^4) ) is ( y' = -9x^8 + 7x^6 - 24x^5 + 16x^3 ).
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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