How do you differentiate #y=x^2y-y^2-xy#?
By signing up, you agree to our Terms of Service and Privacy Policy
Simplify then differentiate to find:
#(dy)/(dx) = 2x-1# when#y != 0#
Multiply by
#(dy)/(dx) = ((2x-1)y)/(x^2-x-1)#
graph{y=x^2y-y^2-xy [-10, 10, -5, 5]}
We can rearrange this as:
Hence:
By signing up, you agree to our Terms of Service and Privacy Policy
To differentiate y=x^2y-y^2-xy, you would use the product rule and the chain rule. The derivative with respect to x is:
dy/dx = 2xy + x^2(dy/dx) - 2y(dy/dx) - y^2 - x(dy/dx)
Then, you would solve for (dy/dx) to find the derivative of y with respect to x.
By signing up, you agree to our Terms of Service and Privacy Policy
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

- 98% accuracy study help
- Covers math, physics, chemistry, biology, and more
- Step-by-step, in-depth guides
- Readily available 24/7