# How do you differentiate #y= e^(1-x) #?

or using logs

graph{(y-2.718281828/(2.718281828^x))=0 [-1, 4, -0.5, 2]}.

graph{(y-2.718281828*((2.718281828)^x^(-2)))=0 [-1, 4, -0.5, 2]}

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To differentiate ( y = e^{1-x} ), you can use the chain rule. The derivative of ( e^{1-x} ) with respect to ( x ) is ( -e^{1-x} ). Therefore, the differentiation of ( y = e^{1-x} ) is ( \frac{dy}{dx} = -e^{1-x} ).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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