# How do you differentiate #y=2 csc x + 5 cos x#?

The derivative is

(I'm going to rearrange a few terms to make it easier to read.)

Rule of the quotient:

I hope this was helpful. That's the answer.

By signing up, you agree to our Terms of Service and Privacy Policy

To differentiate ( y = 2 \csc(x) + 5 \cos(x) ), you would use the rules of differentiation.

The derivative of ( \csc(x) ) is ( -\csc(x) \cot(x) ), and the derivative of ( \cos(x) ) is ( -\sin(x) ).

So, the derivative of ( 2\csc(x) ) is ( -2\csc(x)\cot(x) ), and the derivative of ( 5\cos(x) ) is ( -5\sin(x) ).

Therefore, the derivative of ( y = 2\csc(x) + 5\cos(x) ) is ( y' = -2\csc(x)\cot(x) - 5\sin(x) ).

By signing up, you agree to our Terms of Service and Privacy Policy

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

- 98% accuracy study help
- Covers math, physics, chemistry, biology, and more
- Step-by-step, in-depth guides
- Readily available 24/7