How do you differentiate #(x^2) (sin x)#?

Answer 1

By using the product rule.

Let #f(x) = (x^2)(sinx)#, then #f(x) = g(x) xx h(x)#.
The derivative of this function is given by #f'(x) = (g'(x) xx h(x)) + (h'(x) xx g(x))#
The derivative of #g(x)# or #x^2# is #g'(x) = 2 xx x^(2 - 1) = 2x#
The derivative of #h(x)# or #sinx# is #h'(x) = cosx#.

Using the rule of product:

#f'(x) = (g'(x) xx h(x)) + (h'(x) xx g(x))#
#f'(x) = (2x(sinx)) + (x^2(cosx))#
#f'(x) = 2xsinx + x^2cosx#
Hence, the derivative of #y = (x^2)(sinx)# is #y' = 2xsinx + x^2cosx#.

I hope this is useful!

Sign up to view the whole answer

By signing up, you agree to our Terms of Service and Privacy Policy

Sign up with email
Answer 2

To differentiate the expression ( x^2 \cdot \sin(x) ), you can use the product rule, which states:

[ \frac{d}{dx}(f(x) \cdot g(x)) = f'(x) \cdot g(x) + f(x) \cdot g'(x) ]

Let ( f(x) = x^2 ) and ( g(x) = \sin(x) ).

Now, find the derivatives of ( f(x) ) and ( g(x) ):

For ( f(x) = x^2 ): [ f'(x) = 2x ]

For ( g(x) = \sin(x) ): [ g'(x) = \cos(x) ]

Now, apply the product rule:

[ \frac{d}{dx}(x^2 \cdot \sin(x)) = (2x) \cdot (\sin(x)) + (x^2) \cdot (\cos(x)) ]

[ = 2x \sin(x) + x^2 \cos(x) ]

So, the derivative of ( x^2 \cdot \sin(x) ) is:

[ \frac{d}{dx}(x^2 \cdot \sin(x)) = 2x \sin(x) + x^2 \cos(x) ]

Sign up to view the whole answer

By signing up, you agree to our Terms of Service and Privacy Policy

Sign up with email
Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

Not the question you need?

Drag image here or click to upload

Or press Ctrl + V to paste
Answer Background
HIX Tutor
Solve ANY homework problem with a smart AI
  • 98% accuracy study help
  • Covers math, physics, chemistry, biology, and more
  • Step-by-step, in-depth guides
  • Readily available 24/7