How do you differentiate #log_2 (e)#?

Answer 1

Samantha Adkison

This is a constant. The derivative of any constant, with respect to any variable, is 0.

# log_a a = 1#, #log_e e = (log_2 e) (log_e 2)#. So, # log_2 e = 1/log_e 2 = 1/ln 2# = 1.4427, nearly. .

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Answer 2

Christopher Agresta

To differentiate ( \log_2(e) ), you can use the chain rule. The derivative of ( \log_a(x) ) with respect to ( x ) is ( \frac{1}{x \ln(a)} ). Therefore, the derivative of ( \log_2(e) ) is ( \frac{1}{e \ln(2)} ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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