# How do you differentiate #ln((sin^2)x)#?

Rewrite it first.

By signing up, you agree to our Terms of Service and Privacy Policy

Which means that:

Use implicit differentiation on the left hand side of the equation and the chain rule on the right hand side of the equation:

Simplify the fraction above:

Presto!!

By signing up, you agree to our Terms of Service and Privacy Policy

To differentiate ln((sin^2)x), you can use the chain rule. The derivative of ln(u) with respect to x is (1/u) * du/dx. In this case, u = (sin^2)x. Therefore, du/dx = 2 * sin(x) * cos(x). Substituting these into the chain rule formula, we get:

d/dx [ln((sin^2)x)] = (1/(sin^2)x) * 2 * sin(x) * cos(x)

Simplify the expression:

d/dx [ln((sin^2)x)] = 2 * (cos(x)/sin(x))

Or, alternatively, you can rewrite it as:

d/dx [ln((sin^2)x)] = 2 * cot(x)

By signing up, you agree to our Terms of Service and Privacy Policy

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

- 98% accuracy study help
- Covers math, physics, chemistry, biology, and more
- Step-by-step, in-depth guides
- Readily available 24/7