How do you differentiate #ln(4x)#?

Answer 1

Based on the properties of logarithms:

#ln(4x) = ln4 + lnx#

so:

#d/(dx) ln(4x) = 1/x#

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Answer 2

To differentiate ln(4x), you can use the chain rule of differentiation. The derivative of ln(u) with respect to x is 1/u times the derivative of u with respect to x. In this case, u = 4x. So, the derivative of ln(4x) with respect to x is 1/(4x) times the derivative of 4x with respect to x, which is 4. Therefore, the derivative of ln(4x) with respect to x is 4/(4x), which simplifies to 1/x.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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