How do you differentiate # g(x) =cscx x secx #?
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To differentiate ( g(x) = \csc x  x \sec x ), you can use the following steps:

Differentiate ( \csc x ) with respect to ( x ) using the chain rule: ( \frac{d}{dx}(\csc x) = \csc x \cot x ).

Differentiate ( x \sec x ) using the product rule: ( \frac{d}{dx}(x \sec x) = \sec x + x \sec x \tan x ).

Combine the derivatives obtained in steps 1 and 2 to find the derivative of ( g(x) ): ( g'(x) = \csc x \cot x  (\sec x + x \sec x \tan x) ).
Therefore, the derivative of ( g(x) = \csc x  x \sec x ) is ( g'(x) = \csc x \cot x  (\sec x + x \sec x \tan x) ).
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When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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